Published Sep 12th, 2013, 9/12/13 10:40 am
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Ok I know what you are thinking. There is no such thing as AC current in Redstone. Well you are right...so then how do people create wave generators using DCbatteries?
Basically, instead of creating actual AC current (which is impossible) I configured the component to view the Redstone signal as either positive or negative based on its DC value. So if the Redstone value is 8, the component sees it as +1, likewise, it sees 7 as -1.
This is all explained in this chart:
()-------------------------------------------------------------------------------------------------------------()
Redstone Value: | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 |
Component Value: | -8 | -7| -6 | -5 | -4 | -3| -2 | -1 | 1 |2 | 3 | 4 | 5 | 6 |7 | 8 |
()-------------------------------------------------------------------------------------------------------------()
So why is this relevant? Because the basic idea of an integrator is to show a linear relationship between the input and the output over time... in this case, 1 Redstone tick.
BTW! you can learn more about integrators here: http://en.wikipedia.org/wiki/Op_amp_integrator
real quick: I'm going to be using some funny words here, all you need to know is saturation means a Redstone level of 15 and cutoff means a Redstone value of 0.
So basically, if the Redstone value = 8, the integrator sees it as +1 and will then start to build up to saturation at a rate of 1 Redstone level per 2 ticks (because there are 2 comparators, each at a 1 tick delay) and visa versa, if the Redstone value = 7, the integrator sees it as -1 and will fall into cutoff at a rate of 1 Redstone value per 2 ticks.
likewise, if your Redstone values alternate between 0 and 15, the integrator will see it as -8 and +8 and will rise and fall at a rate 8 Redstone values per 2 ticks. Note that you can use any combination of positive and negative values and it will work just fine. The result will just give you a non-symmetrical triangle wave.
If you watch the video all the way to the end, you'll see another trick you can do with the integrator (hint: it involves something round! something... circular!)
Now there's no world download, only a schematic. the component will behooked up to aninput unit and a read-out meter. the actual integrator is located between the 2 obsidian blocks.
Enjoy!
-n00b_asaurous
Basically, instead of creating actual AC current (which is impossible) I configured the component to view the Redstone signal as either positive or negative based on its DC value. So if the Redstone value is 8, the component sees it as +1, likewise, it sees 7 as -1.
This is all explained in this chart:
()-------------------------------------------------------------------------------------------------------------()
Redstone Value: | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 |
Component Value: | -8 | -7| -6 | -5 | -4 | -3| -2 | -1 | 1 |2 | 3 | 4 | 5 | 6 |7 | 8 |
()-------------------------------------------------------------------------------------------------------------()
So why is this relevant? Because the basic idea of an integrator is to show a linear relationship between the input and the output over time... in this case, 1 Redstone tick.
BTW! you can learn more about integrators here: http://en.wikipedia.org/wiki/Op_amp_integrator
real quick: I'm going to be using some funny words here, all you need to know is saturation means a Redstone level of 15 and cutoff means a Redstone value of 0.
So basically, if the Redstone value = 8, the integrator sees it as +1 and will then start to build up to saturation at a rate of 1 Redstone level per 2 ticks (because there are 2 comparators, each at a 1 tick delay) and visa versa, if the Redstone value = 7, the integrator sees it as -1 and will fall into cutoff at a rate of 1 Redstone value per 2 ticks.
likewise, if your Redstone values alternate between 0 and 15, the integrator will see it as -8 and +8 and will rise and fall at a rate 8 Redstone values per 2 ticks. Note that you can use any combination of positive and negative values and it will work just fine. The result will just give you a non-symmetrical triangle wave.
If you watch the video all the way to the end, you'll see another trick you can do with the integrator (hint: it involves something round! something... circular!)
Now there's no world download, only a schematic. the component will behooked up to aninput unit and a read-out meter. the actual integrator is located between the 2 obsidian blocks.
Enjoy!
-n00b_asaurous
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