An AMA but limited to maths.
Ask away.
Ask away.
52
Oh I didnt see that you stopped, the answer was 3720
Heres an easy one
W=41
X=52
(W x 90) + (X - 22) =?
W=41
X=52
(W x 90) + (X - 22) =?
CobeX7897 was nice enough to create his own thread to continue from mine.
I think I'll stop the maths here. Feel free to start your own thread.
Sorry if I didn't answer your question
Sorry if I didn't answer your question
24+9=6
Why is this so? And what game am I referencing to?
Why is this so? And what game am I referencing to?
y² = x³ - 432
Find all ordered pairs (x,y) so that x and y are integers
Find all ordered pairs (x,y) so that x and y are integers
Am I wrong in saying
y-x=2.75
y-x=2.75
What is 129312904819058158190581123891237289147981749172391795713129481490812048129058012318904518471897135891734713894719237129805813590813058130859018340981850138513589723895728947689347695 divided by 1
TROLOLOLOLOLOL
TROLOLOLOLOLOL
12931290481905815819058112389123728914798174917239179571312948149081204812905801231
That was almost as hard as the 0 + 0 question
That was almost as hard as the 0 + 0 question
12931290481905815819058112389123728914798174917239
17957131294814908120481290580123189045184718971358
91734713894719237129805813590813058130859018340981
850138513589723895728947689347695
too easy
17957131294814908120481290580123189045184718971358
91734713894719237129805813590813058130859018340981
850138513589723895728947689347695
too easy
Something possible but hard:
(((50!)^10)/5)^(5!*50)
(yes i liek the parethesis.. cause im a programmer xD)
and whats the name of this number?
10^(10^100)
(((50!)^10)/5)^(5!*50)
(yes i liek the parethesis.. cause im a programmer xD)
and whats the name of this number?
10^(10^100)
This one's so easy you don't even need to google it. (haha...that's funny)
10^100 is a googol and 10^(10^100) is a googolplex
10^100 is a googol and 10^(10^100) is a googolplex
I did not know that! You learn something new every day.
The simplest answer that I was able to get was (50!^10/5)^6000. No calculator would be able to get a figure higher than 50! without it saying the answer was "infinite."
Also, I couldn't find the name of 10^(10^100) so I found the name of 10^100 instead, which I think is a Thousand Trillion Quadrillion.
Also, I couldn't find the name of 10^(10^100) so I found the name of 10^100 instead, which I think is a Thousand Trillion Quadrillion.
Heres something that might interest you... i'm not entirely sure if its accualy something you could solve because i don't get it at all :p
http://mathworld.wolfram.com/GoldbachConjecture.html
http://mathworld.wolfram.com/GoldbachConjecture.html
Every month, a girl gets allowance. Assume last year she had no money, and kept it up to now. Then she spends 1/2 of her money on clothes, then 1/3 of the remaining money on games, and then 1/4 of the remaining money on toys. After she bought all of that, she had $7777 left. Assuming she only gets money by allowance, how much money does she earn every month?
Good luck bud
Good luck bud
Approximately $2953 per month....that's a lot of pocket money
Whoops....I meant 2592...mixed up the numbers. I couldn't be bothered showing calculations but to prove it
2952x12=31104
31104/2=15552
One third of 15552=5184
15552-5184=10368
One quarter of 10368=2592
10368-2592=7776
There is one dollar difference cause of rounding
2952x12=31104
31104/2=15552
One third of 15552=5184
15552-5184=10368
One quarter of 10368=2592
10368-2592=7776
There is one dollar difference cause of rounding
From my calculations the answer is $15554 per month
12x/24 = 7777
12x = 186648
x = $15554
12x/24 = 7777
12x = 186648
x = $15554
srry you failed the test. its $2222 (if i can believe the internet ofcourse :p )
Source http://library.thinkquest.org/J002235/hard.html its number 10.
Source http://library.thinkquest.org/J002235/hard.html its number 10.
But where is all the working out?
Here's an easy one....what the square root of -100
10i
What is the answer to 50,403,234 divided by 0?
Here is a question that has baffled people for many years.
If we say "how many groups of 2 can you make from six" (or 6 ÷ 2) you would be able to make three groups of 2.
But if we say "how many groups of 0 can you make from 50,403,234" (or 50,403,234 ÷ 0), then we come to this dilema that no matter how many 0s we take from any number, that no groups will have been made.
I believe that there would be an infinite group of zeros.
Remember when 4 ÷ 3 = 1r1 rather than 1.3~?
Well I think it's easiest to say the answer = ∞r50,403,234
If we say "how many groups of 2 can you make from six" (or 6 ÷ 2) you would be able to make three groups of 2.
But if we say "how many groups of 0 can you make from 50,403,234" (or 50,403,234 ÷ 0), then we come to this dilema that no matter how many 0s we take from any number, that no groups will have been made.
I believe that there would be an infinite group of zeros.
Remember when 4 ÷ 3 = 1r1 rather than 1.3~?
Well I think it's easiest to say the answer = ∞r50,403,234
If it were to be given a straight number I agree with 0. Some people say one for some reason. But 0 would probably be the most correct answer possible here. But honestly I am not a mathematician, so idk.
It could be argued that there are an infinite number of 0s or that there are no groups.
But then we could ask ourselves is 0 = nothing?
But then we could ask ourselves is 0 = nothing?
4883x9588x375769x8857x84887586
x5883x9543984x994848x0
x5883x9543984x994848x0
1.3227158*10^25
or
13227158000000000000000000
or
13227158000000000000000000
alright
I have come across the HARDEST math problem EVER!!!!!!!!!!!
It has taken me over and OVER to try and figure it out.
But, since YOU, badguy37, has solved 2+2 my friend....therefor..you MUST know the answer to this problem.....
0+0=???? WHAT IS THE ANSWER???
I have come across the HARDEST math problem EVER!!!!!!!!!!!
It has taken me over and OVER to try and figure it out.
But, since YOU, badguy37, has solved 2+2 my friend....therefor..you MUST know the answer to this problem.....
0+0=???? WHAT IS THE ANSWER???
If there are two sets of zero, if you combine those two zeros, you will still get zero.
In conclusion: 0+0=0
In conclusion: 0+0=0
SO far, I have figured out that the triangle hyp= 75.0102248798 (10dp). Shall do the rest tommorow depending on if I can be bothered
If only I knew what most of that meant...
I don't want to spoil anything but I've answered the question
Click to reveal
I'm clearly doing something wrong with this triganometry... and to think I've recently done an international qualification in maths too!
Square root of 32,410,249?
5693
Potato + Potato!
I know this one... It's Cucumber
badguy37is the triangle scalene?
It should be unless I wrote out the question horribly, it's basic trigonometry, you know Sin, Cos, Tan, righ tangle triangles, all that lovely stuff.
is the triangle scalene?
EDIT also are there any right angles?
EDIT also are there any right angles?
A triangle has three corners A B and C. Angle ABC is 31degrees and side AC is 13.4cm's find the length of side BC and then proceed to use Pythagoras's theorem to find the length of the hypotenuse AB, then proceed to use this value as the length of half of a length of wood used to create a windmill with said triangle being the sail of it, firstly find the circumference of the circle of space this Windmill will rotate in and then the area, then proceed to work out the area of the windmill in total (With the thickness of wood being a total of 2cm thick) and then subtract that from the total area used to find how much space is left over then clearly show a labelled diagram of the windmill in question showing angles and measurments.. Show your workings.
You asked for maths I gave you maths.
You asked for maths I gave you maths.
Having pondered for several seconds, I came to the final answer of 2.
1+1=?
well good job on that
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