1
We Solve Your Math Problems
Hey there. I haven't really seen one of these before, and I really like math. I find it fun to help others in this field. I think this would be a really fun idea. So, here's a scenario in which this thread would be useful.
You have some math homework.
You stumble across a problem that you find difficult.
Some assistance with that particular problem would be nice.
You post your problem below and I, or a fellow helpful person get cracking at it (showing the steps)!
You learn and breeze through the rest of your math homework.
Yay.
Basically you post a math problem and I, or others do our best to solve it and show you how. Please don't abuse it (such as posting your whole assignment), this is meant for learning, not copying answers.
Say you didn't have homework and just want to post a math problem for the heck of it. Why not? :P
I will attempt every problem posted that is Algebra 2, Geometry, Algebra 1, Math 7 and anything else below that. As for others, they could be more knowledgeable in this field.
LEZ GET CRAKIN'!
You have some math homework.
You stumble across a problem that you find difficult.
Some assistance with that particular problem would be nice.
You post your problem below and I, or a fellow helpful person get cracking at it (showing the steps)!
You learn and breeze through the rest of your math homework.
Yay.
Basically you post a math problem and I, or others do our best to solve it and show you how. Please don't abuse it (such as posting your whole assignment), this is meant for learning, not copying answers.
Say you didn't have homework and just want to post a math problem for the heck of it. Why not? :P
I will attempt every problem posted that is Algebra 2, Geometry, Algebra 1, Math 7 and anything else below that. As for others, they could be more knowledgeable in this field.
LEZ GET CRAKIN'!
144
whats the millionth number of Tau after the comma and with the 3?
I literally wrote a program to tell me if your answers are right...
Also, how do we know your not using a calculator XD
Also, how do we know your not using a calculator XD
1 ÷ 0. Simple as that.
Undefined o_O
Google calculator gave me INFINITY!!!
What is 9 devided by the power of 12 squared subtracted with PL28 plus 1,500 times Q minus E22,332 equals X?
That doesn't exist
Uh. I'd recommend a pre-algebra class for you.
Uh it may be to late, but
3564143462x424641463
(NO CALCULATOR)
3564143462x424641463
(NO CALCULATOR)
Find x > 3 such that
ln(x) < x^(0.1)
ln(x) < x^(0.1)
The mean of a set of 5 numbers is 36. The number 132 is removed from the set. By How much the mean is reduced?
5748 Times 3456 Divided by 69 Plus 78 Times 9001
OMG... ITS OVER 9000!!!
No, I'm stupeeeed
OMG... ITS OVER 9000!!!
No, I'm stupeeeed
8x6x7-3+8+90+32-12x29-3+46-0-10x47+56
1+1?
why don't we have these discussions during a separate class such as study hall
it just makes me want to.....
it just makes me want to.....
i love math but i dont think i will be needing your help.....besides arent you cheating??
Whats 4839483 x 4893849348 / 234343
101064255063
3x(4x * 29) = x
FInd x
FInd x
x = 0
x = 0.00287356 also works.
x = 0 would be a more accurate answer. Using 0.00287356 would yield a slightly different answer on the left side.
3x(4x*29) = x
348x^2 = x
348x = 1
x = 1/348
x = 0.00287356321
348x^2 = x
348x = 1
x = 1/348
x = 0.00287356321
1 word, google...
optionaly heres a challenge..
a= x squared, b = -16, x = 8
b(x + 26) * A2?
optionaly heres a challenge..
a= x squared, b = -16, x = 8
b(x + 26) * A2?
Not really a challenge if you ask me, but oh well.
-2228224
Assuming that by A2 you meant A^2
-2228224
Assuming that by A2 you meant A^2
10000000000000000000000000(1a1002010325423+219574289357389b)=?
10000000000000000000000000a + 1.002010325423e+37 + 2.19574289357389e+39b
Simplified:
Simplified:
Click to reveal
10000000000000000000000000a + 10020103254230000000000000000000000000 + 2195742893573890000000000000000000000000
pebble225Swimmer1929pebble225Write ~q -> ~p for the if statement:
If it is raining, then I will not go to the store. ;)
Oh God, I hate these.
If I will go to the store, it is not raining.
wow dude you are ssmmaarrtt... :o
Heh... thanks but it's just basic Geometry :P
I still don't really understand why conditional statements are considered "Geometry".
Swimmer1929pebble225Write ~q -> ~p for the if statement:
If it is raining, then I will not go to the store.
Oh God, I hate these.
If I will go to the store, it is not raining.
wow dude you are ssmmaarrtt...
pebble225Write ~q -> ~p for the if statement:
If it is raining, then I will not go to the store. ;)
Oh God, I hate these.
If I will go to the store, it is not raining.
Write ~q -> ~p for the if statement:
If it is raining, then I will not go to the store.
If it is raining, then I will not go to the store.
So my Math teacher gave us a simple, yet long problem and I'm lazy... 5+3-74-6-3-5-4-5-4-3-4-6-7-8-78-5-4-3-4-5-76-8-8-5-4-3-3-4-6-78-9-8-5-4-3-45-6-76-7+124598372-3958+285892956-693775927496+393859489586-4934759483759+38475857394576 I think I copied it correctly sir.
33241591959699
A genius at work!
Nah man it's just adding and subtracting XD
Thank you so much for this, I'll probably be asking here daily haha
Alright haha!
IT'S
5.654
OBVIOUSLY
5.654
OBVIOUSLY
What if he was serious... and that was actually on his homework... and he wrote your answer down? O_o
GG, then.
Prove that .9999999999... repeating=1
Since the 9's go on FOREVER, there is no number small enough to be the difference between the two.
0.9999... = 1
Thus x = 0.9999...
10x = 9.9999...
10x - x = 9.9999... - 0.9999...
9x = 9
x = 1.This thread has turned into people copy pasting random problems they found on the internet in an attempt to make them look smarter. Seriously, if you googled "hardest math problem ever" and copy pasted it on here, I think I'll be able to know.
144(15/16b+8/9)
Slashes are fractions, not dividing symbols
Slashes are fractions, not dividing symbols
It's the same thing either way...
Are we solving for b?
Yea
135b + 128
lardmaster69Swimmer1929lardmaster69
Actually the correct answer is 3.
The order of operations is the *correct* way to solve that problem.
If you are solving using the order of operations, then (2 + 2 ) /2 = 4
I don't see how the quantity of 2 + 2 is equal to 4...
And if you were solving using the order of operations which is the correct way to solve that problem you would divide 2 by 2 first then add 2, giving you 3.
1. you don't see how 2 + 2 = 4?
2. You only divide 2 by 2 first if it is written 2 + 2 / 2
1.Sorry, I meant I don't see how the quantity of 2 + 2 divided by 2 is equal to 4, which is what you said.
2. Yeah... the way I said it it was written 2 + 2/2 :P There was no "quantity" part.[/quote]
just to clarify, the way you wrote it isn't the only way you could write 2 plus 2 divided by four. There could be parenthesis.[/quote]
My post starts here, the stuff up there are quotes being weird
Erm, no.
If I would have said "The quantity of two plus two divided by four" it would have been 2. But I did not. If quantities are not specified in the problem, there are no parentheses.
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